Problem

5/9

Iterating over the elements of an array

Theory Click to read/hide

When working with arrays, you usually have to work with all the elements of the array at once.
Iterate over elements: we look through all the elements of the array and, if necessary, perform some operation with each of them.
For this, a loop with a variable is most often used, which changes from 0 to N-1, where N  is the number of array elements.
Under N we will consider the current size of the array, that is,
N = A.Length; 

...
for (int i = 0; i < N; i++)
{
     // here we work with A[i]
}
In the specified loop, the i variable will take on the values ​​0, 1, 2, ..., N-1.  Thus, at each step of the loop, we access a specific element of the array with the number i.
That is, it is enough to describe what needs to be done with one element of the A[i] array and place these actions inside such a loop.

Let's write a program that fills the array with the first N natural numbers, that is, at the end of the program, the elements of the array should become equal 
A[0] = 1
A[1] = 2
A[2] = 3
...
A[N - 1] = N
It's easy to see the pattern: the value of an array element must be greater by 1 than the element's index.
The loop will look like this 
for (int i = 0; i < N; i++) { A[ i] = i + 1; }

Problem

Form a loop that fills all array elements with natural number values ​​from 1 to N.

time 1000 ms
memory 256 Mb
Rules for program design and list of errors in automatic problem checking

Teacher commentary

Insert the missing code snippets
C#
1 
N = int(input())
A = [0] * N

# Заполнение массива натуральными числами от 1 до N
2
3 
for i in range (N):
    print(A[i], end=" ")
print()

     

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